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Posted by Pranav Makkar 1 month, 2 weeks ago

CBSE > Class 12 > Applied Mathematics
  • 1 answers

Yash Jain 1 month, 2 weeks ago

P(3) = 0.18

1Thank You

ANSWER

    • Posted by Abhay Verma 1 month, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER
    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Posted by Sayak Mondal 2 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 5 answers

    Sayak Mondal 2 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Sayak Mondal 2 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Sayak Mondal 2 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Sayak Mondal 2 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Sayak Mondal 2 months, 3 weeks ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    ANSWER

    • Posted by Kajal Verma 4 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shalin8 B 4 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shivam Khandelwal 5 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Aman Kumar 5 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Shivansh Kanojia 6 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Kalp Shrimal Jain 6 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Bhumi Goel 7 months, 4 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Devansh Parihar 8 months ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Nisarg Parmar 9 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Royal Baniye 9 months, 2 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Mahitesh Rawat 9 months, 1 week ago

    Continuity ?

    0Thank You

    ANSWER

    • Posted by Sanchita Shrivastava 10 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Sanchita Shrivastava 10 months, 3 weeks ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Ayushi Singh 9 months ago

    I want this

    0Thank You

    ANSWER

    • Posted by Vetali Mittal 11 months, 1 week ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Indhumathi.J Jambu 1 year ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Aikansh Gupta 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Tanushri Bhayani 1 year, 1 month ago

    Kindly provide complete question !!

    0Thank You

    ANSWER

    • Posted by Rupa Josyula 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Lakshya Sharma 11 months ago

    Tatti

    0Thank You

    Pushkar Mahapale 1 year, 1 month ago

    apne iska premium subscription like raha hai kya

    1Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 1 month ago

    The effective rate is the actual rate compounded annually. Therefore, the required sum S is given by
    S = 12000 (1 + {tex}\frac{3}{100}{/tex})10 (1 + {tex}\frac{4}{100}{/tex})4 (1 + {tex}\frac{5}{100}{/tex})2
    {tex}\Rightarrow{/tex} S = 12000 (1.03)10 (1.04)4 (1.05)2
    {tex}\Rightarrow{/tex} S = 12000 (1.34391638) (1.16985856) (1.1025) = 20800.10
    Hence, the amount is ₹20,800.10

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 1 month ago

    ₹2480.57

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 1 month ago

    7

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Tanushri Bhayani 1 year, 1 month ago

    Ohh' alright

    0Thank You

    Nishant Dogra 1 year, 1 month ago

    Using the properties of matrix algebra, we can expand the expression (I + A)3 as follows: (I + A)3 = (I + A)(I + A)(I + A) = (I + A)(I2 + 2IA + A2) = (I + A)(I + 2A + A) = I2 + 3IA + 3A2 + A3 = I + 3A + 3A2 + A3 (since A2 = A) Substituting this expression into the original equation, we get: (I + A)3 - 7A = (I + 3A + 3A2 + A3) - 7A = I + 2A + 3A2 - 7A = I - 5A + 3A2 Therefore, (I + A)3 - 7A is equal to I - 5A + 3A2.

    4Thank You

    ANSWER

    • Posted by Bhumika Jain 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Tanushri Bhayani 1 year, 1 month ago

    Hmm' got it 👍 thanks

    0Thank You

    Nishant Dogra 1 year, 1 month ago

    Solution We can calculate the product AB as follows: AB = [[-i, 0], [0, i]] [[1, 0], [0, -1]] = [[-i, 0], [0, -i]] Next, we can calculate the determinant of AB as follows: det(AB) = (-i) * (-i) - 0 * 0 (determinant of a 2x2 matrix) = 1 Now, we can use the formula for the product of determinants to find the determinant of A multiplied by the determinant of (i^2-1)B: det(A) * det((i^2-1)B) = det(AB) det(A) * (i^2-1)^2 * det(B) = 1 Substituting the known values, we get: det(A) * (i^2-1)^2 * (-1/1) = 1 det(A) * 4 = 1 det(A) = 1/4 Since A is a 2x2 matrix, its determinant can be calculated as follows: det(A) = (-i) * i - 0 * 0 (determinant of a 2x2 matrix) = -1 Therefore, we have a contradiction: det(A) = -1 and det(A) = 1/4. Hence, there is no value of a that satisfies the given conditions.

    1Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Preeti Dabral 1 year, 1 month ago

    Answer is given below:

    1Thank You

    Tanushri Bhayani 1 year, 1 month ago

    Thanks dude

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Preeti Dabral 1 year, 1 month ago

    Answer is given below:

    1Thank You

    Tanushri Bhayani 1 year, 1 month ago

    This was easy but it made me confusing thank you for helping me always

    0Thank You

    ANSWER

    • Posted by Tanushri Bhayani 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 2 answers

    Preeti Dabral 1 year, 1 month ago

    Let the number of guests be x

    If x > 100, then the amount received by the company will be-

    {4800 - 200/10(x - 100)}x

    Now, we need to maximize this amount so let us differentiate with respect to x as follows-

    P = 4800x - 20(x - 100)x

    P = 4800x - 20x² + 2000x

    P = 6800x - 20x²

    dP/dx = 6800 - 40x

    differentiating again-

    d²P/dx² = -40

    As d²P/dx² > 0, the maximum value will occur at dP/dx = 0

    ⇒ 6800 - 40x = 0

    40x = 6800

    x = 6800/40

    x = 170

    Now, the amount received will be =  6800(170) - 20(170)²

    = 1156000 - 578000

    = 578000

    Thus, the maximum amount that the company will receive is 5,78,000 when the number of guests are 170.

    1Thank You

    Tanushri Bhayani 1 year, 1 month ago

    Thank you bro

    0Thank You

    ANSWER

    • Posted by Vaiharai . 1 year, 1 month ago

    CBSE > Class 12 > Applied Mathematics
    • 1 answers

    Preeti Dabral 1 year, 1 month ago

    2 : 3

    0Thank You

    ANSWER

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