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  • 2 answers

Preeti Dabral 1 year, 2 months ago

Distance covered by a boat in 5 hours = 36 km
Rate upstream of boat {tex}=\frac{36}{5}{/tex} 7.2 kmph
Speed of the stream = 2.4 kmph
{tex}\therefore{/tex} Speed of the boat in still water
= (7.2 + 2.4) kmph
= 9.6 kmph
{tex}\therefore{/tex} Rate downstream of the boat
= (9.6 + 2.4) kmph
= 12 kmph
{tex}\therefore{/tex} Time taken in covering 78 km distance
{tex}=\frac{78}{12}{/tex}
= 6.5 hours or 6 hour 30 minutes.

Tanushri Bhayani 1 year, 2 months ago

Thanks a lot dude 😇
  • 2 answers

Preeti Dabral 1 year, 2 months ago

Let P be the principal at any time t. According to the given problem, {tex}\frac{d p}{d t}=\left(\frac{5}{100}\right) \times \mathrm{P}{/tex}
or {tex}\frac{d p}{d t}=\frac{\mathrm{P}}{20}{/tex} ...(i)
separating the variables in equation (i), we get
{tex}\frac{d p}{\mathrm{P}}=\frac{d t}{20}{/tex} ...(ii)
Integrating both sides of equation (ii), we get
log P = {tex}\frac{t}{20}{/tex} + C1
or P = {tex}e^{\frac{t}{20}} \cdot e^{\mathrm{C}_{1}}{/tex}
or P = {tex}\mathrm{C} e^{\frac{t}{20}}{/tex} (where eC1 = C) ...(iii)
Now, P = 1000, when t = 0
Substituting the values of P and t in (iii), we get C = 1000. Therefore, equation (iii), gives
P = 1000 et/20
Let t years be the time required to double the principal. Then 2000 = 1000 et/20 {tex}\Rightarrow{/tex} t = 20 loge2.

Tanushri Bhayani 1 year, 2 months ago

Thames bro 😘
  • 1 answers

Tanishka Solanki 1 year, 2 months ago

X^2÷2
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Tanushri Bhayani 1 year, 2 months ago

You will need to do all coz every formula has its own way of solving the question better start learning all u still hve 13 days for exam to go Best of luck 👍..
  • 1 answers

Tanushri Bhayani 1 year, 2 months ago

Need to prepare a spreadsheet presentation on matrix and function separately This project was given in our school And in RKC project was related probability and linear equations Project are given by the school faculty as there no particular viva taken by external faculty and the school faculty itself takes the viva ....
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Preeti Dabral 1 year, 4 months ago

Please provide complete information. 

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Tanushri Bhayani 1 year, 2 months ago

f(x)=x^5 f'(x)=5x^4 f"(x)=20x^3. (;5×4=20)

Kushal Sethi 1 year, 6 months ago

20x^3
  • 4 answers

Tanushri Bhayani 1 year, 2 months ago

Here you go ... they are taken from the sample paper

Tanushri Bhayani 1 year, 2 months ago

CASE STUDY – III According to an educational board survey, it was observed that class XII students apply at least one to four weeks ahead of colleges application deadline. Let X represent the week when an average student applies ahead of a college’s application deadline and the probability of student to get admission in the college 𝑃(𝑋 = 𝑥) is given as follows: 𝑃(𝑋 = 𝑥) = { 𝑘𝑥 6 𝑤ℎ𝑒𝑛 𝑥 = 0, 1 𝑜𝑟 2 (1 − 𝑘)𝑥 6 𝑘𝑥 2 𝑤ℎ𝑒𝑛 𝑥 = 3 𝑤ℎ𝑒𝑛 𝑥 = 4 0 𝑤ℎ𝑒𝑛 𝑥 > 4 Where k is a real number. Based on the above information, answer the following questions. Show steps to support your answers. a) Find the value of k. 1 b) What is the probability that Sonali will get admission in the college, given that she applied at least 2 weeks ahead of application deadline? 1 c) Calculate the mathematical expectation of number of weeks taken by a student to apply ahead of a college’s application deadline. OR To promote early admissions, the college is offering scholarships to the students for applying ahead of deadline as follows: ₹ 50000 for applying 4 weeks early, ₹ 20000 for applying 3 weeks early, ₹ 12000 for applying 2 weeks early, and ₹ 9600 for applying 1 week early What is the expected scholarship offered by the college?

Tanushri Bhayani 1 year, 2 months ago

CASE STUDY – I An overhead water tank has three pipes A, B and C attached to it (as shown in figure (II)). The inlet pipes A and B can fill the empty tank independently in 15 hours and 12 hours respectively. The outlet pipe C alone can empty a full tank in 20 hours. Based on the above information, answer the following questions. a) For a routine cleaning of the tank, the tank needs to be emptied. If pipes A and B are closed at the time when the tank is filled to two-fifth of its total capacity, how long will pipe C take to empty the tank completely? 1 b) How long will it take for the empty tank to fill completely, if all the three pipes are opened simultaneously? 1 c) On a given day, pipes A, B and C are opened (in order) at 5 am, 8 am and 9 am respectively, to fill the empty tank. In how many hours will the tank be filled completely? OR Given that the tank is half-full, only pipe C is opened at 6 AM, to empty the tank. After closing the pipe C and an hour’s cleaning time, tank is filled completely by pipe A and B together. What is the total time taken in the whole process?

Tanushri Bhayani 1 year, 2 months ago

When observed over a long period of time, a time series data can predict trend that can forecast increase or decrease or stagnation of a variable under consideration. Such analytical studies can benefit a business for forecasting or prediction of future estimated sales or production. Mathematically, for finding a line of best-fit to represent a trend, many methods are available. Methods like moving-averages and least-squares squares are some of the techniques to predict such trends. Mrs. Shamita runs a bread factory and the record of her sales of bakery items for the period of 2015 - 2019 is as follows: Year 2015 2016 2017 2018 2019 Sales (in ₹ thousands) 35 42 46 41 48 Based on the above information, answer the following questions. Show steps to support your answers. a) By taking year 2017 as origin, use method of least-squares to find the best-fit trend line equation for Mrs. Shamita’s business. Show the steps of your working. OR Demonstrate the technique to fit the best-suited straight-line trend by the method of 3-years moving averages. Also draw the trend line. 2 b) What are the estimated sales for Mrs. Shamita’s business for year 2022? 1 c) Mrs Shamita wishes to grow her business to yearly sale of ₹ 67400. In which year will she be able to reach her target?
  • 1 answers

Preeti Dabral 1 year, 4 months ago

We have
f (x) = 2x3 – 6x2 + 6x + 5
or f ′(x) = 6x2 – 12x + 6 = 6 (x – 1)2
Now, f ′(x) = 0
{tex}\Rightarrow{/tex} x = 1
Thus, x = 1 is the only critical point of f . We shall now examine this point for local maxima and/or local minima of f. Observe that f ′(x) {tex}\ge{/tex} 0, for all x {tex}\in{/tex} R and in particular f ′(x) > 0, for values close to 1, to the left and to the right of 1. Therefore, by first derivative test, the point x = 1 is neither a point of local maxima nor a point of local minima. Hence x = 1 is a point of inflexion.

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Tanushri Bhayani 1 year, 2 months ago

-3x+logx/x^4 is the ans
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Tanushri Bhayani 1 year, 2 months ago

(x+2)^3/3+c is the answer
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Preeti Dabral 1 year, 4 months ago

Speed of the man in still water =8 kmph.
Speed of the river =2 kmph
Downstream =8+2=10 kmph
Upstream =8−2=6 kmph
{tex}\Rightarrow \frac{x}{10}+\frac{x}{6}=\frac{48}{60}{/tex}
⇒8x=24
⇒x=3 km

  • 1 answers

Preeti Dabral 1 year, 4 months ago

Cost of raw material = x²

Cost of transportation = 2x

Property tax = 5,000

Therefore ,

(i) C(x) = x² + 2x + 5000

(ii) MC = 2x + 2

Now, x = 21,

MC = 2(21) + 2 = 42 + 2 = 44

(iii) x = 50,

MC. = 2(50) + 2 = 100+2 = 102

  • 1 answers

Preeti Dabral 1 year, 4 months ago

{tex}\begin{aligned} & \text { We know } \mathrm{V}=\frac{\mathrm{A}}{\mathrm{r}}\left[1-(1+\mathrm{r})^{-\mathrm{n}}\right] \\ & \text { Thus } 30000=\frac{\mathrm{A}}{0.12}\left[1-(1+0.12)^{-20}\right] \\ & \Rightarrow \mathrm{A}=\frac{30000 \times 0.12}{\left[1-(1+0.12)^{-20}\right]} \\ & \Rightarrow \mathrm{A}=\frac{3600}{\left[1-(1.12)^{-20}\right]} \\ & \Rightarrow \mathrm{A}=\text { Rs. } 4016.76 \end{aligned}{/tex}

  • 2 answers

Tanushri Bhayani 1 year, 2 months ago

P=R/I; R=20000 and I=10years×4=40 P=20000÷40 P=500 Therefore, he must keep ₹500 every quarterly for 10 years to accumulate the actual amount.

Husan Preet 2 years, 1 month ago

20000 N=10*4=40 So 20000÷40 = 5000
  • 1 answers

Gembali Harsha Vardhan 2 years, 6 months ago

When B runs 50 m, then A runs 45 m. When B runs 1000 m, then A runs (45/50) x 1000 m = 900 m ∴ B beats A by 100 m.
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Gembali Harsha Vardhan 2 years, 6 months ago

Let 2 white ball be denoted by W₁, W₂ & red ball by r We draw two balls, one after the other Sample space = S = {(W₁, W₁), (W₂, W₂), (W₁, W₂), (r, W₂), (W₂, r), (W₂, W₁), (r, w₁), (W₁, r), (r, r)} Let X: Number of red balls in two draws We can see there are 0 red, 1 red and 2 red balls So, X = 0 or X = 1 or X = 2
  • 2 answers

Madhav Kaushik 2 years, 5 months ago

Hello

Gembali Harsha Vardhan 2 years, 6 months ago

Given An ice-cream parlour receives a customer at an average rate of 4 per minute. If the number of customers received by the parlour follows a Poisson distribution, To Find the approximate probability that 16 customers will be coming to the parlour in a particular 4-minute period on a given day Solution: an average rate of 4 per minute. => an average rate of 4* 4 per 4 minute. => an average rate of 16 per 4 minute. Hence mean = 16 λ = 16 = P(x) = λx e^(-^) / x! P(16) = 16¹6e-16/16! = 0.099 = 0.1

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