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Evaluate :- sin[π/2 -sin^-1 (-√3/2)]

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Evaluate :- sin[π/2 -sin^-1 (-√3/2)]

    • Posted by Vinod Varma 4 years, 6 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Jaspreet Singh 4 years, 5 months ago

    Let sin-¹ [-√3/2] = ¤ ¤ = -π/3 A. T. Q = Sin[π/2 + π/3] = Sin [5π/6] = sin 150• = sin (90 + 60)• = sin 90 + cos 60 + cos 90 + sin 60 = 1×1/2. + 0 × √3/2 = 1/2 = ANWSER...........!!!!!!!

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