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Sin(1/2 cos inverse 4/5)

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Sin(1/2 cos inverse 4/5)

    • Posted by Manjari Tripathi 4 years, 6 months ago

    CBSE > Class 12 > Mathematics
    • 2 answers

    Jaspreet Singh 4 years, 5 months ago

    Let cos -¹ 4/5 = ¤ B/H = 4/5 = cos ¤ Sin ¤/2 = √1-cos ¤ / √2 = 1/√10

    0Thank You

    Vinod Varma 4 years, 6 months ago

    Let, cos inverse 4/5 = A where, A belongs to [0,π] So, cosA = 4/5 .............(1) We know, cos2A = 1 - 2sin^2A cosA = 1- 2sin^2 A/2 2sin^2 A/2 = 1 - cosA sin^2 A/2 = (1 - cosA)/2 Put cosA = 4/5 in equation (1) = (1-4/5)/2 = (5-4)/5/2 = 1/5 . 1/2 = 1/10 sin^A/2 = 1/10 sin A/2 = +1/√10 (sin A/2 is +ve and 0 <A<π/2) A/2 = sin inverse (1/√10) sin (1/2 .A) = sinA/2 sinA/2 = sin (sin inverse 1/√10) So, sin(sin inverse 1/√10) = 1/√10

    0Thank You

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