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Matric chap 3.4 question no 12

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Matric chap 3.4 question no 12
  • 2 answers

Jasleen Kaur 5 years, 5 months ago

I can try to assist u...? Ques is ...[6 -3] [-2 1] ?Sol:- A=IA [6 -3]=[1 0]A [-2 1] [0 1] R2---3R2 [6 -3]=[1 0]A [-6 3]. [0 1] R1---R1+R2 [0 0]=[1 1]A [-6 3]. [0 1] We have all zeros in the row 1 on L.H.S ...hence it's inverse doesn't exist .bcz we have to make it an identity matrix..as it doesn't happen .Hence conclusion is that it's inverse does not exist.. HOPE IT WOULD HAVE HELPED U...? ????️...?*ask anytime for help*..?

Jitesh Rana 5 years, 5 months ago

A-1dose not exist
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