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Evaluate sin( 2Sin inverse3/5)

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Evaluate sin( 2Sin inverse3/5)

    • Posted by Karishma Markam 5 years, 6 months ago

    CBSE > Class 12 > Mathematics
    • 4 answers

    Nishihoney Lodha 5 years, 6 months ago

    Ques. Sin(2sin^-1[3/5]) --sol. Let sin^-1[3/5]=A.... Sin2A=2sinAcosA.... As sin^-1[3/5]=A.... SinA=3/5 CosA=4/5 Cos^-1[4/5]=A Putting the values : 2sin[sin^-1(3/5)]cos[cos^-1(4/5)].... 2.(3/5).(4/5)=24/25

    0Thank You

    Ayush Vishwakarma?? 5 years, 6 months ago

    Not 5he it is the

    0Thank You

    Ayush Vishwakarma?? 5 years, 6 months ago

    The answer is 24/25. Firstly you have to solve 2sin^-1 3/5 in tan^-1 and apply 5he formula 2tan^-1.

    0Thank You

    Apratim Sarkar 5 years, 6 months ago

    I think 6/5

    0Thank You

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