Evaluate :- 1+i2+i4+i6+.................+i2n
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Posted by Shriom Yadav 6 years, 9 months ago
- 3 answers
Sudha Malamal 6 years, 9 months ago
if n is odd the answer will be zero
if n is even all cancel and answer is 1
Sahdev Sharma 6 years, 9 months ago
We know i2= -1
And {tex}i^4=(i^2)^2=(-1)^2= 1{/tex}
So all the terms having i will be cancelled out. We ll get answer as 1
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Sunil C N 6 years, 9 months ago
if n is even answer is zero
if n is odd answer is one
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