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Using differentials find the approximate value …

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Using differentials find the approximate value of under cube root 27

    • Posted by Yuvraj Ranjan 5 years, 8 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Somya Sharma 5 years, 8 months ago

    Let y=x^1/3. For all x=27. (1) y+∆y=(x+∆x)^1/3. For all ∆x=0. (2) (2)-(1) ∆y=(x+∆x)^1/3-x^1/3 (x+∆x)^1/3=∆x × dy/dx +x^1/3 27^1/3= 0×dy/dx + 27^1/3 27^1/3=3

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