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A die is thrown three times …

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A die is thrown three times E:4 appears onthird toss F:6 and 5 appears on first 2 tosses

Posted by Amit Gavel 5 years, 8 months ago

CBSE > Class 12 > Mathematics

1 answers

Sakshi Mittal 5 years, 8 months ago

S=(111,112,113--------666)=216 E=(114,124------164,214,224------264, 314,324-----364,314,324---364,414,424-----464,514,524,564,614,624,----664)=36 F=(651,652,653,654,655,656)=6 Eintersectionf=(654)=1 Now, p(E/F)=p(EintersectionF)/p(F)------(1) and P(E)=36/216=1/6 P(F)=6/216=1/36 P(EintersectionF)=1/216 Then,(1) becomes ( 1/216)/(1/36)=1/6 which is required answer Thanks 4 watching

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