A bag contains 50 tickets numbered …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Ananya Singh 1 year, 3 months ago
- 0 answers
Posted by Sanjay Kumar 1 year, 3 months ago
- 0 answers
Posted by Xxxxxx Xx 1 year, 2 months ago
- 3 answers
Posted by Charu Baid 1 year, 2 months ago
- 0 answers
Posted by Sanjna Gupta 1 year, 2 months ago
- 4 answers
Posted by Karan Kumar Mohanta 1 year, 2 months ago
- 0 answers
Posted by Sneha Pandey 1 year, 3 months ago
- 0 answers
Posted by Xxxxxx Xx 1 year, 2 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Yogita Ingle 5 years, 8 months ago
Total number of elementary events =<nobr aria-hidden="true">50C5</nobr>
Given,third ticket =30
=> first and second should come from tickets numbered 1 to 29 =<nobr aria-hidden="true">29C2</nobr>
ways and remaining two in<nobr aria-hidden="true"> 20C2</nobr><nobr aria-hidden="true"></nobr>
ways.
Therfore, favourable number of events = <nobr aria-hidden="true">29C2*20C2</nobr>
Hence,required probability = <nobr aria-hidden="true">29C2*20C2/50C5</nobr> =551 / 15134
1Thank You