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(2i+6j+27k)×(i+pj+qk)=0 Find value of p and …

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(2i+6j+27k)×(i+pj+qk)=0 Find value of p and q

    • Posted by Aman Kumar 5 years, 8 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Tejaswani Bhargav 5 years, 8 months ago

    By determinant method we can do cross product. | i j k | | 2 6 27 | | 1 p q | Now solve this determinant i(6q-27p)-j(2q-27)+k(2p-6) = 0 Now Take 2p-6=0 p=3 Then take (2q-27) = 0 q = 27/2 I hope it helped u ?

    2Thank You

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