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Find the vector of equation of …

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Find the vector of equation of the plane passing through the three points with position vectors i^+j^-2k^,2i^-j^+k^ and i^+2j^+k^ .also find the coordinates of point of intersection of this plane and the line r vector is equal to 3i^-j^-k^+meu(2i^-2j^+k^

Posted by Mohit Mishra 5 years, 8 months ago

CBSE > Class 12 > Mathematics

2 answers

Arun Kumar 5 years, 8 months ago

Now to find point write all points lying on line and put in eq. Of plane

Arun Kumar 5 years, 8 months ago

Given points that the vector contains are (1,1,-2);(2,-1,1) and (1,2,1). Let Direction ratio of plane be (a,b,c) So eq. Of plane = a(x-x1)+ b(y-y1)+c(z-z1)=0 Using given one point in eq. We have : a(x-1)+b(y-1)+c(z+2)=0 Also other 2 points will satisfy the eq. Also so on equating the points as x,y and z in eq. We have a-2b+3c=0 b+3c=0 Solve the eq. And put value of a,b and c in eq. Of plane which is req. Plane

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