Find the area of a right …
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Sahdev Sharma 6 years, 9 months ago
Using Pythagoras Theorm
{tex}Height = \sqrt {(hypotenuse)^2-(base)^2}{/tex}
{tex}= \sqrt{625-49}{/tex}
{tex}= \sqrt{576}= 24 {/tex} cm
Area of ∆ = {tex}{1\over 2}\times base\times height{/tex}
= {tex}{1\over2}\times 7\times 24= 84\ cm^2{/tex}
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