(SinA +1-cosA)/(cosA-1+sinA ) =1+sinA/cosA
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Posted by Aditya Narayan Panda 6 years, 9 months ago
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Joshina Learnel 6 years, 9 months ago
divide numerator and denomintor of LHS by cos A
{tex}LHS=\frac{tan A+sec A-1}{1-sec A+tanA} but 1=sec^2A-tan^2A LHS=\frac{tan A+sec A-(sec^2A-tan^2A)}{1-sec A+tanA} =\frac{tan A+sec A-(secA-tanA)(secA+tanA)}{1-sec A+tanA} from the numerator take (sec A+tan A) =\frac{(tan A+sec A)(1-(secA+tanA)}{1-sec A+tanA} cancel (1-(secA+tanA) =tanA+secA =\frac{sinA}{cosA}+\fract{1}{cosA} =\fract{sinA+1}{cosA {/tex}
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