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(SinA +1-cosA)/(cosA-1+sinA ) =1+sinA/cosA

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(SinA +1-cosA)/(cosA-1+sinA ) =1+sinA/cosA

Posted by Aditya Narayan Panda 8 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Joshina Learnel 8 years, 4 months ago

divide numerator and denomintor of LHS by cos A

{tex}LHS=\frac{tan A+sec A-1}{1-sec A+tanA} but 1=sec^2A-tan^2A LHS=\frac{tan A+sec A-(sec^2A-tan^2A)}{1-sec A+tanA} =\frac{tan A+sec A-(secA-tanA)(secA+tanA)}{1-sec A+tanA} from the numerator take (sec A+tan A) =\frac{(tan A+sec A)(1-(secA+tanA)}{1-sec A+tanA} cancel (1-(secA+tanA) =tanA+secA =\frac{sinA}{cosA}+\fract{1}{cosA} =\fract{sinA+1}{cosA {/tex}

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