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Y=sin inverse x show that (1-xsquare)second …

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Y=sin inverse x show that (1-xsquare)second derivative-xfirst derivative
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Dolly ?️ 5 years, 9 months ago

Y= sin-¹(x) Then, y' = 1/√(1-x²) √(1-x²).y'= 1 [squaring bothside (1-x²).(y')² =1 Differentiate both side again -2x.(y')² + 2y'.y"(1-x²)= 0 Divide by 2y' bothe side
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