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X=a sec O ,y= b tanO …

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X=a sec O ,y= b tanO differentiation

    • Posted by Arvind Singh 5 years, 10 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Life & Education 5 years, 10 months ago

    dx/dO=secO.tanO dy/dO=sec^2O dy/dx =dy.dO/dO.dx =sec^2O/secO.tanO =secO/tanO =(1/cosO).(cosO/sinO) =1/sinO =cosecO

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