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If x^y - y^x = a^b …

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If x^y - y^x = a^b , find dy/dx.

    • Posted by Sejal Uniyal 5 years, 11 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Ritss ?? 5 years, 11 months ago

    X^y - y^x = a^b Taking log on both the side Log X^y - Log y^x = log a^b Now, Y. Log x - x. Log y = b. Log a Differentiate wrt x dy/dx. Logx +y/x - Log y - x/y. dy/dx = 0 y/x - log y = dy/dx (x/y - Log x ) dy/dx= (y/x - Log y ) / ( x/y - Log x )

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