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sin^1x-cos^x=π/6

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sin^1x-cos^x=π/6
  • 1 answers

Dolly ?️ 5 years, 11 months ago

Sin^-1(x)= π/6+cos^-1(x) X= sin{π/6+ cos^-1(x)} X= sin(π/6).cos[cos^-1(x)]+cos(π/6).sin[cos^-1(x)] X= 1/2.x + √3/2.√(x^2-1) X= 3(x^2-1) X=3x^2-3 3x²-x-3=0 Now you can solve the quadratic.!?
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