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Integration 1+sinx in root dx

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Integration 1+sinx in root dx
  • 2 answers

Anshu Dwivedi 5 years, 11 months ago

Ans=- 2cosx/2+2sinx/2 +c

Ananya Mishra 5 years, 11 months ago

Put 1 as sin2x/2 + cos2x/2 and sinx as 2sinx/2cosx/2 then it will become (sinx/2+cosx/2) its whole square then the root will get removed and it will become integration of sinx/2+cosx/2 and now integrate it using basic rules
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