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A spherical soap bubble is expanding …

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A spherical soap bubble is expanding so that its radius is increasing at the rate of 0.02 cm per second at what rate is a surface area in using when its radius is 5 cm take Pi equal to 3.14
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Sorry by mistake!! It happened given dr/dt,=0.02 cm per second and then surface area of soap bubble 4πr^2 on differentiating we get 4*π*2r*dr/dt put value of r=5cm then on substitution, we get answ
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