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find the equation of the tangent to the curve y=(x-7)/(x-2)(x-3),at the point where it cuts x-axis

Posted by Abdus Samad 6 years ago

CBSE > Class 12 > Mathematics

1 answers

Manas Mishra 6 years ago

The point at which it cuts x axis then y=0 at that point. So, in the given equation on putting y=0 we get x= 7 then differentiate the given equation by applying quotient rule. Then put the value (7,0) in differentiated function then you get dy/dx the use the basic slope point form equation (y-y.)= dy/dx (x-x.). Then you'll get your answer..

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