No products in the cart.

1^3+2^3+3^+___+n^3={n(n+1)/2}^2

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

1^3+2^3+3^+___+n^3={n(n+1)/2}^2
  • 1 answers

Divyanshi Nagpal 4 years, 7 months ago

step 1 : put n=1 p(1) = 1=1 step 2 : let the result true for n = k p(k) : 1^3 + 2^3 +_________+k^3 = {k(k+1)/2}^2 __(1) step3 : show the result is true for n=k+1 p(k+1) = 1^3+2^3+______+(k+2)
http://mycbseguide.com/examin8/

Related Questions

What is sin60
  • 4 answers
Option of photo
  • 0 answers
Derivative of cube root of tanx
  • 0 answers
Solve cos2x -5sinx -3=0
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App