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Integration of sin4xsin8x (any other method …

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Integration of sin4xsin8x (any other method than using the formula 2sinxsiny)
  • 2 answers

Pooja Bhakar 6 years ago

Sin4x(2Sin4xCos4x)dx = 2Sin^2 4x Cos4x dx now put sin4x =t so that cos4x dx =4dt we get 8t^2dt now you can solve it easily after solving put the value of t in answer.......

Dolly ?️ 6 years ago

Sin4x(2sin4x.cos4x) 2.sin^2(4x).cos4x 2{(1-cos2(4x))÷2}.cos4x Cos4x - cos8x.cos4x 1/2{2cos4x-2cos8x.Cos4x} 1/2{2cos4x - cos12x - cos4x} 1/2{cos4x - cos12x} 1/2{sin4x/4 -sin12x/12}
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