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Integration of dx/4 cosx+3 sinx

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Integration of dx/4 cosx+3 sinx
  • 2 answers
1/2(2/5 log (2+tanx/2 upon 2-tanx/2))

Pooja Bhakar 6 years ago

Firstly we put cosx=cos^2 x/2-sin^2 x/2 and sinx = 2sinx/2cosx/2 then dividing numerator and denominator by cos^2 x/2 then we get the result in form of sec and tan after that put tanx/2=t so that 1/2sec^2 x/2dx=dt i.e. sec^2 x/2 = 2dt then solve it by partially method . I hope this answer will help you...
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