Factorise:- 9x²+6x+1-25y²
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Posted by Piyush Singh 6 years, 10 months ago
- 2 answers
Naveen Sharma 6 years, 10 months ago
Ans.
{tex}9x^2+6x+1-25y^2{/tex}
{tex}= (3x)^2+(2\times 3x\times 1)+(1)^2-25y^2{/tex} [using {tex}(a+b)^2 = a^2+2ab+b^2{/tex}]
{tex}= (3x+1)^2-(5y)^2{/tex}
{tex}= (3x+1-5y)(3x+1+5y){/tex} [using {tex}a^2-b^2 = (a+b)(a-b)]{/tex}
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Hans Raj 6 years, 9 months ago
{tex}9x^2+6x+1-25y^2{/tex}.......................... {tex}(3x)^2 + (2x3xx1) + (1)^2 -25y^2{/tex}.................................applying Rule {tex}(a+b)^2 = a^2+b^2+2ab {/tex}
.{tex}(3x + 1)^2 - (5y)^2{/tex} ........................... . {tex}(3x+1+5y)(3x+1-5y){/tex} .................................. .... applying Rule {tex}a^2 - b^2 = (a+b) (a-b){/tex}
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