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∫x³-1/x³+x dx

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∫x³-1/x³+x dx

Posted by Harshit Sharma 5 years, 10 months ago

CBSE > Class 12 > Mathematics

1 answers

Bhawna Thakur 5 years, 9 months ago

First divide this term After that we will get I = |[1-(x+1)/(x³+x)]dx I = |[1]dx -|[(x+1)/(x³+x)]dx Let I' = |1dx & I" = | (X+1)/(X³+X)dx From I" we will get again two terms ,one will be having x as nume. & second will be having 1 as nume. In 1st term u will get x common and final term will be 1/(x²+1²) In 2nd term let x² be t , then u will get final term be [1/(t²+t)]dt then in final integrate all the terms u r getting U will get final answer be I = x - [ tan‐¹x + log|x²/(x²+1)| ] + C where C is ur any constant.

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