Find dy÷dx if y=log(sinx)

dy/dx = d {log(sin x)} /dx = cosx / sinx = cot x [As diff. of log t = 1/t and diff. of sinx = cos x, that's why, by chain rule d{log(sinx)} /dx = cotx ]

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Nishu Sahu 6 years, 1 month ago

Cotx

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