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Tan inverse =cosx\1+sinx

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Tan inverse =cosx\1+sinx
  • 3 answers

Mukan Jangra????? 6 years, 1 month ago

Samaj aya

Mukan Jangra????? 6 years, 1 month ago

1+sinx= (cos²x/2 +sin²x/2 +2cosx/2sinx/2)=( cosx/2+sinx/2)² Canel with numerator. Tan inverse (1-tanx/2)/(1+tanx/2)= Tan inverse [ tan(pi/4-x/2)]=pi/4- x/2 ans.

Mukan Jangra????? 6 years, 1 month ago

Cosx= cos²x/2-sinx²/2 =( cosx/2-sinx2)(cosx/2 + sinx/2) (Cosx/2+ sinx/2 ) cancel with denominator square of it Then both numerator and denominator divide by cosx/2
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