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Sin^8x-cos ^8x=(sin ^2x-cos ^x) (1-2sin^2cos^x)?

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Sin^8x-cos ^8x=(sin ^2x-cos ^x) (1-2sin^2cos^x)?
  • 1 answers

Rock ×Himanshu 4 years, 8 months ago

Change (cos x^2)3-(cosx^2)3
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