an isosceles triangle has perimeter 30 …
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Rashmi Bajpayee 6 years, 10 months ago
Perimeter of Isosceles triangle = 30 cm
Each of equal side of given triangle = 12 cm
Let the third side be x cm
=> 12 + 12 + x = 30
=> x = 30 - 24 = 6 cm
Now, Semi-perimeter (s) = {tex}{{30} \over 2} = 15{/tex} cm
Using Heron's formula,
Area of given triangle = {tex}\sqrt {s\left( {s - a} \right)\left( {s - b} \right)\left( {s - c} \right)} {/tex}
= {tex}\sqrt {15\left( {15 - 12} \right)\left( {15 - 12} \right)\left( {15 - 6} \right)} {/tex}
= {tex}\sqrt {15 \times 3 \times 3 \times 9} {/tex}
= {tex}9\sqrt {15} {/tex} sq. cm
= 9 x 3.87
= 34.83 sq. cm
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