Solve for x and y ax/b …
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Posted by Ashraful Hassan 4 years, 9 months ago
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Sia ? 4 years, 9 months ago
The given equations may be written as
{tex}a^2x - b^2y = a^2b + ab^2{/tex} ....... (i)
{tex}ax - by = 2ab{/tex} ......... (ii)
Multiplying (ii) by b and subtracting the result from (i),
{tex}(a^2 - ab)x = a^2b - ab^2{/tex}
{tex}\Rightarrow{/tex} {tex}(a^2 - ab)x = b(a^2 - ab){/tex}
{tex}\Rightarrow{/tex} {tex}x = b.{/tex}
Putting {tex}x = b{/tex} in (ii), we get
{tex}a b - b y = 2 a b {/tex}
{tex}\Rightarrow b y = - a b{/tex}
{tex} \Rightarrow y = \frac { - a b } { b } = - a{/tex}
Hence, x = b and y = -a.
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