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When 1.5g of non-volatile solute was …

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When 1.5g of non-volatile solute was dissolved in 90g of benzene, the boiling point of benzene raised from 353.23K-353.93K. calculate the molar mass of the solute.(kb for benzene=2.52kg/mol)

Posted by Furrukh Shaaz 4 years, 9 months ago

CBSE > Class 12 > Chemistry

1 answers

Anushka Tripathi 3 years, 1 month ago

ΔT b =353.93K−353.23K=0.7K Substituting W B =1.5g,W A =90g,ΔT b =0.7K,K b =2.52Kkgmol −1 in the expression M B = ΔT b ×W A K b ×W B ×1000 , we get M B = 0.7K×90g 2.52Kkgmol −1 ×1.5g×1000gkg −1 M B =60gmol −1

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