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Find dy/dx Sin^2y + cos xy …

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Find dy/dx Sin^2y + cos xy = k

Posted by Abhimanyu Kaul 6 years, 2 months ago

CBSE > Class 12 > Mathematics

3 answers

Abhimanyu Kaul 6 years, 2 months ago

Thanks

Parteek Gurjar 6 years, 2 months ago

Differentiate with respect to x d/dxsin^2y+d/dxcosxy=d/dx'k' 2cos.dy/dx-sinxy(x.dy/dx+y.d/dx)=0 2cos.dy/dx-sinxy.x.dy/dx+y.1=0 2cos.dy/dx-sinxy.x.dy/dx+y=0 2cos.dy/dx-sinxy.x.dy/dx=-y 2cos. dy/dx-x.dy/dx=-y/sinxy dy/dx(2cos-x)=-y/sinxy dy/dx=-y/sinxy(2cos-x)

Pari Goyal 6 years, 2 months ago

Ysinxy/2sin4y-xsinxy

ANSWER

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