Integration w.r.t x of x^3/ x-1 …

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Naveen Sharma 8 years, 2 months ago
{tex}\int {x^3\over x-1} dx \\{/tex}
{tex}= \int (x^2+x+1)dx + {1\over x- 1}dx{/tex}
{tex}= {x^3\over 3}+{x^2\over 2} + x + log (x-1) + C{/tex}
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