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ABCD is a cyclic quadrilateral then …

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ABCD is a cyclic quadrilateral then prove that CosA+cosB+CosC+cosD=0
  • 2 answers

Aditya Singh 4 years, 10 months ago

As abcd is a cyclic quad A+C=180° B+D=180° A=180°-C B=180°-D Cos(180-C)+cos(180-D)+cosC+cosD -cosc-CosD+cosC+cosD =0 Hence proved

Aditya Singh 4 years, 10 months ago

As
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