How to locate √x on number ...

How to locate √x on number line
  • 1 answers

Sia 🤖 7 months, 2 weeks ago

We can write 10 as
{tex}10 = 9 + 1 = 3^2 + 1^2{/tex}
Draw OA = 3 units, on the number line
Draw BA = 1 unit, perpendicular to OA.
Join OB

Now, by Pythagoras theorem,
{tex}OB^2 = AB^2 + OA^2\\ OB^2 = 1^2 + 3^2 = 10{/tex}
{tex}\Rightarrow \quad O B=\sqrt{10}{/tex}
Taking O as centre and OB as a radius, draw an arc which intersects the number line at point C.
Clearly, OC corresponds to {tex}\sqrt{10}{/tex} on the number line.

Related Questions:

  • 0 answers
What is 64raise to 1÷2
  • 6 answers

Buy Complete Study Pack

Subscribe complete study pack and get unlimited access to selected subjects. Effective cost is only ₹ 12.5/- per subject per month. Based on the latest CBSE & NCERT syllabus.

myCBSEguide App


Trusted by 70 Lakh Students

CBSE Test Generator

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

Work from Home

  • Work from home with us
  • Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection