Line x=2 and parabola y2 =8x
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Sia ? 6 years, 4 months ago
We have, y2 = 8x and x = 2
{tex}\therefore{/tex} Area of shaded region, {tex}A = 2\int_0^2 {\sqrt {8x} dx = 2.2\sqrt 2 \int_0^2 {{x^{1/2}}dx} } {/tex}
{tex}= 4.\sqrt 2 .\left[ {2.\frac{{{x^{3/2}}}}{3}} \right]_0^2 = 4\sqrt 2 \left[ {\frac{2}{3}.2\sqrt 2 - 0} \right]{/tex}
{tex}= \frac{{32}}{2}{/tex} sq units
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