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| x x.x 1+ px.x.x| | …

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| x x.x 1+ px.x.x| | y y.y 1+py.y.y | = (a-b)(b-c)(c-a) | z z.z 1+pz.z.z| (a+b+c) (a.a+b.b+c.c) Prove that

    • Posted by Shubhdeep Sidhu 6 years, 5 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Shubhdeep Sidhu 6 years, 5 months ago

    This is of determinant chapter

    0Thank You

    ANSWER
    http://mycbseguide.com/examin8/

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