A pendulum bob of mass 80mg …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
A pendulum bob of mass 80mg carrying a charge of 2 * 10-8 C is at rest in a horizontal uniform electric field of 2*104 Vm-1.Find the tension in the thread of the pendulum and the angle it makes with the vertical.
Posted by Vishnumaya Menon 6 years, 10 months ago
- 2 answers
Payal Singh 6 years, 10 months ago
Given: mass = 80 mg = 80 × 10-6 Kg
Charge q = 2 × 10-8 C
E = 2 × 104 Vm-1
Let T is tension in string and {tex}\theta{/tex}
is angle of string with vertical.
In equilibrium
{tex}Tsin\theta = qE \ ....(1){/tex}
{tex}Tcos\theta = mg \ ....(2){/tex}
Divide (1) by (2), we get
{tex}tan\theta = {qE\over mg}{/tex}
=> {tex}tan \theta = {2\times 10^{-8}\times 2\times 10^4\over 80\times 10^{-6}\times 10}{/tex}
=> {tex}tan \theta = 0.5{/tex}
=> {tex}\theta = 27^°{/tex}
Now Tension T = {tex}qE\over sin \theta{/tex}= {tex}{2\times 10^{-8}\times 2\times 10^4\over sin 27^°}{/tex}
= 8.8 × 10-4 N
Related Questions
Posted by Sanjana Mehra 1 week, 3 days ago
- 0 answers
Posted by Ashish Ranjan 2 weeks, 2 days ago
- 1 answers
Posted by Diksha Sharma 2 weeks, 1 day ago
- 0 answers
Posted by Sunem Dungdung 2 weeks, 4 days ago
- 0 answers
Posted by Suhani Sharma 1 week, 4 days ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Mayank Gautam 5 years, 4 months ago
1Thank You