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sin[cot-'(x+1)]=cos(tan-'x) find x

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sin[cot-'(x+1)]=cos(tan-'x) find x

    • Posted by Monika Mishra 6 years, 5 months ago

    CBSE > Class 12 > Mathematics
    • 1 answers

    Sachin Upreti 6 years, 5 months ago

    Sin{sin(1/√x^2+2x+2)}=cos{cos(1/√x^2+1)} = (1/√x^2+2x+2)= 1/√x^2+1 Both side squaring And solve the equation

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