Find the zero of the quadratic …
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Naveen Sharma 6 years, 11 months ago
Ans. To find zeros, we ll equate it with 0
=> x2 - 2x - 8 = 0
=> x2 - 4x + 2x - 8 = 0
=> x(x-4) + 2( x-4) = 0
=> (x - 4) ( x + 2 ) = 0
=> x - 4 = 0 Or x + 2 = 0
=> x = 4, -2
Zeros of the polynomial are 4 , -2
On comparing with ax2 + bx + c, we get a = 1, b = -2 and c = -8
We know Sum of zeroes = {tex}-{b\over a}{/tex}
=> 4 + (-2) = {tex}- {-2\over 1}{/tex}
=> 2 = 2
Again Product of zeroes = {tex}c\over a{/tex}
=> {tex}4 \times (-2) = {-8\over 1}{/tex}
=> -8 = -8
Hence verified
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