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Integration of 1/(sin⁴x+cos⁴x+sin²x.cos²x)

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Integration of 1/(sin⁴x+cos⁴x+sin²x.cos²x)
  • 1 answers

Mona Singh 6 years, 7 months ago

Whenever the question has even power of cos or sin.. Divide numerator and denominator by that even power of sec.. In this question we will divide by sec^4x.. And then put tanx =z.. The final answer will be.. 1/√3 (tan-1(tan^x -1/√3 tanx) ) +C..
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