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Tan^-1(x-1/x+1)+tan^-1(2x-1/2x+1)=tan^-1(23/36)

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Tan^-1(x-1/x+1)+tan^-1(2x-1/2x+1)=tan^-1(23/36)
  • 2 answers

Nivetha Vijayakumar 6 years, 7 months ago

I think that we have to find the value of ' x ' coz the RHS only contain the constant values. If my guess was correct, then x = 1 or x = -1/2.

Nivetha Vijayakumar 6 years, 7 months ago

Should we find the value of 'x' here?
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