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If y=1+(1/x)+(1/x^2)+(1/x^3)...to infinity and |x|>1 , …

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If y=1+(1/x)+(1/x^2)+(1/x^3)...to infinity and |x|>1 , then dy/dx is equal to ?
  • 1 answers

Sanskriti S 6 years, 9 months ago

y=x/(x-1) , (Using sum of infinite GP, a/(1-r)) so,dy/dx=1/(x-1)^2
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