(a+b) ka whole five
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Ram Kushwah 5 years, 2 months ago
{tex}\begin{array}{l}(\mathrm a+\mathrm b)^5=(\mathrm a+\mathrm b)^{2\;}\times(\mathrm a+\mathrm b)^2\;\times(\mathrm a+\mathrm b)\\=(\mathrm a^2+2\mathrm{ab}+\mathrm b^2)\;\times\;(\mathrm a^2+2\mathrm{ab}+\mathrm b^2)\;\times(\mathrm a+\mathrm b)\\\mathrm{Now}\;\mathrm{you}\;\mathrm{solve}\;\mathrm{yourself}\end{array}{/tex}
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