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TanA=a\a+1 tanB=1/2a+1 Find A+B

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TanA=a\a+1 tanB=1/2a+1 Find A+B
  • 1 answers

Dolly ?️ 5 years, 2 months ago

Tan(A+B) =tanA+tanB/(1-tanA.tanB) Tan(A+B) =a/(a+1)+1/(2a+1) ÷ 1-a/(a+1)(2a+1) Tan(A+B) = a(2a+1)+(a+1) / (a+1)(2a +1)-a Tan(A+B)=1 Tan(A+B)=Tan¶÷4 A+B=¶÷4
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