Limits 0 to 5 integral of| …

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Posted by Neelam Donkal 6 years, 9 months ago
- 2 answers
Gaurav Seth 6 years, 9 months ago
{tex}Let I = ∫50[|x| + |x−2| + |x−5|] dx =∫20[x − (x − 2) − (x − 5)] dx + ∫52[x + (x − 2) − (x−5)] dx =∫20(7−x) dx + ∫52(x + 3) dx=[7x − x22]20 + [x22 + 3x]52 =[(14−2) − 0] + [(252 + 15) − (2 + 6)]=12 + 552 − 8 =4 + 552=632{/tex}
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Gaurav Seth 6 years, 9 months ago
The below solution is as per this ques: Integral 0-5 |x|+|x-2|+x-5|.dx
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