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Limit 0to pie by 2 log(tanx+cotx) …

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Limit 0to pie by 2 log(tanx+cotx) integration
  • 1 answers

Suhani Rana? 6 years, 10 months ago

log(tanx+cotx) dx log(sinx/cosx + cosx/sinx) dx log(sin^2+cos^2x/sinxcosx) dx log(1/sinxcosx) dx log1 - log(sinxcosx) -[log(sinx)+log(cosx)] Now just integrate with taking limits that given in question
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