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sin xy + x/y= x^2 -y …

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sin xy + x/y= x^2 -y find dy/dx
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Gaurav Mukesh 6 years, 10 months ago

Sinxy+x/y=x^2-y d.w.r. to x Cosxy. ( xdy/dx+y) + (y-xdy/dx)/y^2=2x-dy/dx when arrange dy/dx in one side ,we get dy/dx=(2xy-y^2cosxy-1)/xycosxy-x+y
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